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Vanadium Ionization Energy

The Vanadium Ionization Energy is the energy required to remove from atom one mole of electrons with subsequent production of positively charged ion of Vanadium.
V -> V+ + e-
This process can be repeated many times, but the energy cost is increased dramatically. The general equation for the Vanadium is:
VN+ -> V(N+1)+ + e-

Ionization Energy

V -> V1+ = 650 kJ/mol = 155.50 Kcal/mol
V1+ -> V2+ = 1414 kJ/mol = 338.28 Kcal/mol
V2+ -> V3+ = 2828 kJ/mol = 676.56 Kcal/mol
V3+ -> V4+ = 4507 kJ/mol = 1078.23 Kcal/mol
V4+ -> V5+ = 6294 kJ/mol = 1505.74 Kcal/mol
V5+ -> V6+ = 12362 kJ/mol = 2957.42 Kcal/mol
V6+ -> V7+ = 14489 kJ/mol = 3466.27 Kcal/mol
V7+ -> V8+ = 16760 kJ/mol = 4009.57 Kcal/mol
V8+ -> V9+ = 19860 kJ/mol = 4751.20 Kcal/mol
V9+ -> V10+ = 22240 kJ/mol = 5320.57 Kcal/mol

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